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【大学数学】g(f(x))が恒等関数かつf(g(x))が恒等関数でないは、ありえ【微分積分】C09｜すうがくのす


Solved Consider the ring: δ:K L;δ(X)=(x,0) Show that the | Chegg.com


An illustration of g(x) = σσ(x) − σ( x+δ−1 δ ), where σ(x) = max{0, x ...